목록영어 끝말잇기 (2)
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[Programmers/Python] 영어 끝말잇기
출처 https://programmers.co.kr/learn/courses/30/lessons/12981 소스 12345678910111213141516171819202122232425262728293031def solution(n, words): answer = [] flag = 0 a = 0 b = 0 for i in range (1, len(words)): p1 = words[i-1] p2 = words[i] for j in range(0, i): if (words[j] == words[i]): flag = 1 break len_p1 = len(p1) if (p1[len_p1 -1] != p2[0]): flag = 1 if flag : a = (i % n) + 1 b = int(i / n) + 1..
Algorithm/Programmers
2019. 3. 21. 23:39
[Programmers/C++] 영어 끝말잇기
출처https://programmers.co.kr/learn/courses/30/lessons/12981 소스12345678910111213141516171819202122232425262728293031323334353637383940#include #include #include using namespace std; vector solution(int n, vector words) { int flag = 0; int a = 0; int b = 0; vector answer; for(int i = 1; i
Algorithm/Programmers
2019. 3. 21. 23:21